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Lecture 07 - Elastica 1

We are going to be studying 'elastic' curves.

Definition

Bending energy of a curve (which will be a conserved quantity) is defined to be:

El=12∫0Lκ2ds

If we also want to twist the curve then:

E^l=12∫0Lκ2ds+∫0Lτ2ds

We want to obtain the equations of motion from the bending energy of a curve.


Consider a regular curve in Euclidean space R3, defined on a fixed interval [a1,a2]. (One can do the same on a Riemannian manifold instead by replacing derivatives with covariant derivatives instead).

Let Ω={γ : γ(ai)=αi,γ′(ai)=αi′}, now consider the subspace of Ω such that:

Ωu={γ∈Ω : ||γ′||=1}

Elastica minimizes the bending energy that is:

F=12∫γκ2ds=12∫γ||γ″||2ds

We are interested in varying F subject to the constraint of the defined subspace, thus we define Fλ(γ)=12∫||γ″||2+Λ(s)(||γ′||2−1)ds, where Λ is the langrange multiplier. Lagrange multiplier says that the minimum of F on Ωu is a stationary point for Fλ for some values of Λ(s).

Derivation of equations of motion

If w be a vector along γ:

∂Fλ(w)=∂∂ϵFλ(γ+ϵw)|ϵ=0

We first compute the Fλ on the right:

Fλ(γ+ϵw)=12∫a1a2||(γ+ϵw)″||2+Λ(s)(||(γ+ϵw)′||2−1)ds

Thus:

∂ϵFλ(γ+ϵw)|ϵ=0=∫a1a2(γ″⋅w″+Λ(s)γ′⋅w′)ds=0

Integrating by parts gives us:

∫a1a2[γ‴−(Λγ′)′]⋅wds+(γ″⋅w″−(Λγ′−γ‴)⋅w)|a1a2

Thus we obtain our Equations of motion:

E(γ)=γ‴−(Λγ′)′=0(*)⟹γ‴−Λγ′=J

Da Rios Equation from the Elastic equations

γ′=T⟹γ″=κN∴γ‴=−κ2T+κ′N+κτB

Thus (∗) transforms to:

(−κ2−Λ(s))T+κ′N+κτB=J

Differentiating gives us:

(−3κκ′−Λ′)T−(κ″−κ3−Λκ−κτ2)N+(κτ′+2κ′τ)B=0

Thus we obtain Λ(s) by projecting the above equation on T.

Λ(s)=−32κ2+λ2

where λ is some constant. Thus substituting back we obtain:

J=κ2−λ2T+κ′N+κτB

Thus once again differentiating we obtain our Da Rios equation:

κ″+12κ3−κτ2−λκ2=0,κτ′+2κ′τ=0.

We obtain from the second equation that (κ2τ)′=0 implies κ2τ=c1, thus reducing our system to:

κ″+12κ3−c12κ3−λκ2=0.

Notice that 2J=κ2−λT+2κ′N+2κτB, thus:

(**)4||J||2=(κ2−λ)2+4κ′2+4κ2τ2=a2

Taking u=κ2 then (∗∗) reduces to:

(u−λ)2+u′2u+4τ2u=a2

Let u′2=P(u) and multiply u both sides of the equation then:

P(u)=−u3+2λu2+(a2−λ2)u−4τ2

Notice the following:

Thus P(u) has 3 real roots thus:

P(u)=−(u+α1)(u+α2)(u+α3)

Thus:

4λ=α3+α2−α1a2−λ2=α1α3+α1α2−α2α34τ2=α1α2α3

After some laborious calculation:

u(s)=α3(1−q2sn2(rs,p))

where:

p2=−α3−α2α3+α2q2=α3−α2α3α3=k02r=12α3+α1ω2=p2q2κ2=κ02(1−p2ω2sn2(k02ωs,p)